134=-16t^2+129t+2

Solution for 134=-16t^2+129t+2 equation:

134=-16t^2+129t+2

We move all terms to the left:

134-(-16t^2+129t+2)=0

We get rid of parentheses

16t^2-129t-2+134=0

We add all the numbers together, and all the variables

16t^2-129t+132=0

a = 16; b = -129; c = +132;
Δ = b2-4ac
Δ = -1292-4·16·132
Δ = 8193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-129)-\sqrt{8193}}{2*16}=\frac{129-\sqrt{8193}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-129)+\sqrt{8193}}{2*16}=\frac{129+\sqrt{8193}}{32}
$